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已知一个二叉树和一个key,写一个函数打印出这个二叉树中已知节点的所有祖先节点。
例如:如果已知的树是下面的二叉树,而且key是7,然后你的function应该打印出4,2和1。
1 / \ 2 3 / \ 4 5 / 7
// Java program to print ancestors of given node/* A binary tree node has data, pointer to left child and a pointer to right child */class Node { int data; Node left, right, nextRight; Node(int item) { data = item; left = right = nextRight = null; }}class BinaryTree { Node root; /* If target is present in tree, then prints the ancestors and returns true, otherwise returns false. */ boolean printAncestors(Node node, int target) { /* base cases */ if (node == null) return false; if (node.data == target) return true; /* If target is present in either left or right subtree of this node, then print this node */ if (printAncestors(node.left, target) || printAncestors(node.right, target)) { System.out.print(node.data + " "); return true; } /* Else return false */ return false; } /* Driver program to test above functions */ public static void main(String args[]) { BinaryTree tree = new BinaryTree(); /* Construct the following binary tree 1 / \ 2 3 / \ 4 5 / 7 */ tree.root = new Node(1); tree.root.left = new Node(2); tree.root.right = new Node(3); tree.root.left.left = new Node(4); tree.root.left.right = new Node(5); tree.root.left.left.left = new Node(7); tree.printAncestors(tree.root, 7); }}// This code has been contributed by Mayank Jaiswal
输出:
4 2 1
时间复杂度是:O(n),在这里n是已知二叉树中节点的数目。
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